Light Up asks two questions at once: does each numbered wall have the right number of lights, and can every open cell be lit? This small board shows how the two questions help answer each other.

A quick reminder of the rules: a light shines along its row and column until it hits a wall, and lights its own cell too. Two lights can’t shine on each other. A numbered wall needs exactly that many lights directly above, below, left or right of it. Diagonals don’t count. The Light Up guide has more.

Row 1, column 1: plain wall
Row 1, column 2: unlit space
Row 1, column 3: unlit space
Row 1, column 4: unlit space
Row 2, column 1: 1 wall
Row 2, column 2: unlit space
Row 2, column 3: unlit space
Row 2, column 4: unlit space
Row 3, column 1: 0 wall
Row 3, column 2: 2 wall
Row 3, column 3: unlit space
Row 3, column 4: unlit space
Row 4, column 1: unlit space
Row 4, column 2: unlit space
Row 4, column 3: 2 wall
Row 4, column 4: unlit space

Starting board

Four numbered walls, eleven open cells

Rows run top to bottom and columns left to right. Dark squares are walls. The sun symbol is a light, and shaded cells are lit. In these diagrams an × marks a cell that can’t hold a light; you won’t need to mark these in the game.

1. Start with the tightest walls

The 1 in row 2, column 1 has only one open neighbour: the cell to its right. The edge of the board, the plain wall above and the 0 below block everything else, so that cell gets a light. It lights the rest of row 2 and the cell above it, and stops at the 2 below.

The 0 in row 3, column 1 says its only open neighbour, row 4, column 1, can’t hold a light. That cell still has to be lit by something, though. “No light here” doesn’t mean “this cell can stay dark”.

Row 1, column 1: plain wall
Row 1, column 2: lit space
Row 1, column 3: unlit space
Row 1, column 4: unlit space
Row 2, column 1: 1 wall
Row 2, column 2: light
Row 2, column 3: lit space
Row 2, column 4: lit space
Row 3, column 1: 0 wall
Row 3, column 2: 2 wall
Row 3, column 3: unlit space
Row 3, column 4: unlit space
Row 4, column 1: unlit space, cannot contain a light
Row 4, column 2: unlit space
Row 4, column 3: 2 wall
Row 4, column 4: unlit space

One forced light, one ruled-out cell

The outlined light satisfies the 1. The bottom-left cell can’t hold a light, so another light has to reach it.

2. Light the bottom-left corner

Light can’t reach row 4, column 1 from above, because the 0 is a wall, and the cell itself is ruled out. Looking right along row 4, the only open cell before the next wall is row 4, column 2, so the light must go there. This time the deduction came from a cell that needs light, not from a wall asking for one.

Row 1, column 1: plain wall
Row 1, column 2: lit space
Row 1, column 3: unlit space
Row 1, column 4: unlit space
Row 2, column 1: 1 wall
Row 2, column 2: light
Row 2, column 3: lit space
Row 2, column 4: lit space
Row 3, column 1: 0 wall
Row 3, column 2: 2 wall
Row 3, column 3: unlit space, cannot contain a light
Row 3, column 4: unlit space
Row 4, column 1: lit space, cannot contain a light
Row 4, column 2: light
Row 4, column 3: 2 wall
Row 4, column 4: unlit space

Only one cell can reach the corner

The 2 in row 3, column 2 now has lights above and below it. That’s its full count, so its last open neighbour, row 3, column 3, can’t hold a light.

3. Finish the bottom wall

The 2 in row 4, column 3 already has a light on its left. The cell above it was just ruled out, and below it is the edge of the board. The only place left for its second light is on its right, in row 4, column 4. That light also brightens the right-hand column.

Row 1, column 1: plain wall
Row 1, column 2: lit space
Row 1, column 3: unlit space
Row 1, column 4: lit space
Row 2, column 1: 1 wall
Row 2, column 2: light
Row 2, column 3: lit space
Row 2, column 4: lit space
Row 3, column 1: 0 wall
Row 3, column 2: 2 wall
Row 3, column 3: unlit space, cannot contain a light
Row 3, column 4: lit space
Row 4, column 1: lit space, cannot contain a light
Row 4, column 2: light
Row 4, column 3: 2 wall
Row 4, column 4: light

Every numbered wall is satisfied

Both 2s have their two lights. But row 1, column 3 is still dark, which is a good reminder that correct counts don’t guarantee a finished board.

4. One dark cell left

Which cell could light row 1, column 3? Its neighbours on either side are already lit by other lights, so a light in either would see one of them. Below it, row 2, column 3 is in the first light’s line of sight, and row 3, column 3 was ruled out by the satisfied 2. The wall in row 4 blocks the column after that. That leaves only the dark cell itself.

Row 1, column 1: plain wall
Row 1, column 2: lit space
Row 1, column 3: light
Row 1, column 4: lit space
Row 2, column 1: 1 wall
Row 2, column 2: light
Row 2, column 3: lit space
Row 2, column 4: lit space
Row 3, column 1: 0 wall
Row 3, column 2: 2 wall
Row 3, column 3: lit space, cannot contain a light
Row 3, column 4: lit space
Row 4, column 1: lit space, cannot contain a light
Row 4, column 2: light
Row 4, column 3: 2 wall
Row 4, column 4: light

Coverage finishes the job

The last light brightens the top row and the cells below it. All eleven open cells are lit, every numbered wall has its count, and no two lights can see each other.

Three checks for every board

After each light, check the numbered walls nearby, the cells it can see, and the cells that are still dark. A fully lit board can hide two lights that see each other, and correct counts can still leave a dark corner. You need all three.

This board was made for the lesson and checked for a single solution; it isn’t from the Daily set or the Weekly collection. Try Light Up in the Library when you’re ready for a fresh layout.